What is the Domain of this Inverse Function?

What is the domain of this inverse function?

g(x) = squareroot(x)

Therefore the domain is [0,infinity)

g^(-1) (x) = x^2
That's the inverse function


Is the domain of this inverse function [0,infinity) ?

:wiggle:

 

The domain would be all real numbers because any number you will plug in x (negatives and such) will give you a real number.

 

Oh, actually I got it mixed up, so you are correct.

I was thinking of a regular function f(x) = x^2.

The OP wrote the domain of the inverse function.. I forgot that the when it's inverse.. the domain & range switches around from the normal/original function.

So.. the range of x^2 is [0,infinity) that means the inverse of g(x) = x^2 domain will be [0,infinity).

 

why is my post count 0?

 

?

let g(x) be the inverse of f(x)

f(x) = sqrt(x)
Domain: [0, ∞)
Range: [0, ∞)

g(x) = x²
Domain: (-∞, ∞)
Range: [0, ∞)

 

O ya the inverse function of sqrt(x) isn't a complete x^2 but the right side of it. so the domain is [0, infinity)