Help? If log2n^(1944)=logn^(486sqr2) determine the value of n^6? Anyone know how to go about solving this?
Log(2*n^1844)=log(n^486*sqrt(2))? sqrt is square root Is that what you're asking? The equation is hard to read. Try typing it into equations editor in word.
i think it would be better if you wrote it on a piece of paper and post the picture or use paint and hand write the equation cause im confused about it slightly
Yeah, its all good anyways, I already got someone to solve it for me. Thanks to the people who responded though.
