Any math whizzes in here??? :( I desperately need help on this question I got from class. If anyone knows how to solve it, please kindly help! Problem: Three clans of ninjas are meeting for a showdown. Ninjas aren't a terribly loyal or honorable group and many belong to more than one clan. 47% are ninjas of the sword 53% are ninjas of the fist 45% are ninjas of the night 20% are both ninjas of the sword and ninjas of the fist 15% are both ninjas of the sword and ninjas of the night 13% are both ninjas of the fist and ninjas of the night 3% belong to all three clans Question: What is the probabiliity that a ninja belongs to exactly one clan? Gosh I suck at math. Thank god this isn't going to be due until next week >.<
If you assume that the ninjas belonging to two clans only belong to two clans and do not intersect with the 3% that belong to all 3 clans, draw out the venn diagram. then P(sword only) = 0.47 - 0.20 - 0.03 - 0.15 = 0.09 P(fist only) = 0.53 - 0.20 - 0.03 - 0.13 = 0.17 P(night only) = 0.45 - 0.15 - 0.13 - 0.03 = 0.14 Add all 3 probabilities up = 0.09 + 0.17 + 0.14 = 0.40 = 40%
Which math class are you in? Need to know what methods of solving we can use Anyways... did anyone else at 40%?
Whaaa! Thanks shy!!!! I totally forgot to post up the answer to this question because it's an odd number and they have it in back of the book. I just wanted to find out the method on how to solve it. -sweat I have one more math problem I need help with: One-quarter of a number increased by one-half the same number is twelve. Find the number. This one's even so it's not in the back.
If increased means "Add"... (.25)x+(0.5)x = 12 0.75x=12 x=16 16 The joys of spending Friday nights studying for finals :( Finals start in a few days... -cry2
My gosh, what a nice thread. Came just in time for me too! Anyone good with Calculus in here? Problem: Table 1: 236 226 191 189 196 Table 2: 181 176 181 186 179 183 Conduct a test of the hypothesis that Table 2 is more effective for maintaing a lower amount than table 1. Be complete in your answer. Be sure to include all parts of the hypothesis testing procedure. Do we use a one-sided test or a two-sided test? And I know that we are supposed to use a t-procedure for this. Thanks! Also, a few questions for Chemistry: 14. Boron has two isotopes: born -10 and boron -11. Which is more abundant, given that the atomic mass of boron is 10.81? 15. There are three isotopes of silicon; they have mass numbers of 28, 29, and 30. The atomic mass of silicon is 28.086 amu. Comment on the relative abundance of these three isotopes. 16. The element copper has naturally occurring isotopes with the mass numbers of 63 and 65. The relative abundance and atomic masses are 69.2% for mass = 62.93 amu. Calculate the average atomic mass of copper. 17. Calculate the atomic mass of bromine. The two isotopes of bromine have atomic masses and relative abundance of 78.92 amu (50.69%) and 80.92 amu (49.31%). Thanks in advance!!!
mystery: you’re welcome If you need any more help with math problems, just post them here & I’ll see what I can do. avant: "The joys of spending Friday nights studying for finals :( Finals start in a few days... -cry2" So, is this where you go to spend your study breaks?? peachey: use a 1 sided test. A one-sided test is a statistical hypothesis test in which the values for which we can reject the null hypothesis, H0 are located entirely in one tail of the probability distribution. In other words, the critical region for a one-sided test is the set of values less than the critical value of the test, or the set of values greater than the critical value of the test. So, suppose we wanted to test a manufacturers claim that there are, on average, 50 matches in a box. We could set up the following hypotheses: H0: µ = 50, against H1: µ < 50 or H1: µ > 50 Either of these two alternative hypotheses would lead to a one-sided test. Presumably, we would want to test the null hypothesis against the first alternative hypothesis since it would be useful to know if there is likely to be less than 50 matches, on average, in a box (no one would complain if they get the correct number of matches in a box or more). Yet another alternative hypothesis could be tested against the same null, leading this time to a two-sided test: H0: µ = 50, against H1: µ not equal to 50 Here, nothing specific can be said about the average number of matches in a box; only that, if we could reject the null hypothesis in our test, we would know that the average number of matches in a box is likely to be less than or greater than 50. For the chemistry problems: 16. This is a weighted averaging, which is multiplying values by coefficient weights and dividing by the sum of the weights. Average Atomic Mass for this case ONLY is: 0.692*62.93+0.308*65 which is ~ 63.5 AMU. Note that this is under the assumption that 63 and 65 are the two highest abundance isotopes of this element. 17. 0.5069*78.92+0.4931*80.92=79.9062 . Same thing. You just do a weighted average calculation. No idea how to do the other 2 problems. When is this due? PS: Woah...3 smilies all in one reply??? Oh, wait. NVM...because 2 of them were quoted from AVANT's post. Go figure? ahaha
-lol Now that's an equation that's not hard to solve! lol heheh j/k Avant! Thank you so much for your help on that second math problem! You guys are the best. And good luck with your finals!
14) Boron -11 is more abundant. That's why the average atomic mass is closer to 11. 15) Same logic as 14, there are overwhelming silicon -28 than the other two isotopes. That's why the amu is only a little bit above 28. Don't try using humor to avoid the truth. Both of you know you love me -cool
ahhh! what a great thread!!! okay i need help with english...we are studying for the SATs >.< #2. The puppy __________ is without a home has just been sold. a. which b. , which c. , that d. that e. who #3. __________ the books down on the floor. a. Lie b. Lye c. Lay d. Laid e. Lain #5. Just between __________, the corpse is hidden in the garage. a. you and me b. you and I c. me and you d. I and you e. us #8. Everybody was satisfied with __________ grade. a. they're b. there c. their d. their own e. her #10. __________ we go to the store, or __________ you? a. Shall, shall b. Shall, will c. Will, shall d. Should, shall e. Will, would #11. He wants to __________ where no man has gone before. a. go boldly b. gone boldly c. boldly go d. go with bold e. go bold #15. There __________ trees in this forest than in the one by our house. a. is less b. are less c. are lesser d. are fewer e. is fewer #16. Choose which sentence is written correctly. a. ''What do you think about 'No new taxes?''' he asked her. b. ''What do you think about 'No new taxes'?'', he asked her. c. ''What do you think about 'No new taxes?','' he asked her. d. ''What do you think about 'No new taxes'?'' he asked her. e. What do you think about 'No new taxes','' he asked her. #19. Choose the sentence with a misplaced modifier: a. Running at top speed, I felt my wig fly off. b. We had a great time at his party, dancing until dawn. c. He kicked the ball barely twenty yards. d. The camera photographed the satellite hurtling through space. e. The soccer team only won four games the entire season. Any help would be good! thanks!!!!! BTW, "shy", I think I saw you at another forum? (wuxia one) is that you??
ahahaha of course! yeah, it is isn't it?! What! You mean shy's been two-timing this forum with another forum??? -shock
Woah... I think someone needs to let some hot air out of their head! blackmagic: 2. d 3. c 5. b 8. not sure about this one, but I know it's either (c) or (e) 10. b (?) 11. c (?) 15. d 16. d 19. A misplaced modifier is simply a word or phrase describing something but not placed near enough the word it is supposed to modify. The modifying word or phrase is not dangling; no extra words are needed; the modifier is just in the wrong place. Incorrect: I had to take down the shutters painting the house yesterday. So I'm guessing the answer to this one would either be (c) or (e) again, although I'm not sure. Perhaps someone else here knows? omg, no. I used to be a member on another forum years ago, but ever since I found my true love, aka PA, I broke up with the other forum.
I think it would have helped you a lot more if you were to guess what the answers were first. It is a prep class after all, you should know why the answer is and not just know what the answer is. But since shy already answered, I'll just add some answers too. 8. c - Not e because Everybody isn't one person. 10. b 11. c
omg, no. I used to be a member on another forum years ago, but ever since I found my true love, aka PA, I broke up with the other forum.[/QUOTE] You broke up with another forum? The forum must by really sad haha lol. Btw Mystery this was really goood thread . I'm happy that you make this thread.
oh my gosh, thanks for the help Avant and Shy! okay... shy, don't get mad at me but I accidently wrote the wrong thing. It's suppose to be: One-sample t test or two-sample t test Not one-sided or two sided, sorry!!! Helpy please...:( And one other question: What is S(3 / [cos(3t)] dt = ??? The answer key to that, I think, is Ln|sec(3t)+tan(3t)| But I still need the step by step approach for solving it. Thanks in advance!
problem #1: 2 sample t-test. A two sample t-test is a hypothesis test for answering questions about the mean where the data are collected from two random samples of independent observations, each from an underlying normal distribution: When carrying out a two sample t-test, it is usual to assume that the variances for the two populations are equal, i.e. The null hypothesis for the two sample t-test is: H0: µ1 = µ2 That is, the two samples have both been drawn from the same population. This null hypothesis is tested against H1: µ1 > µ2 problem #2: use u-substitution. u=3t du=3*dt solve for dt=du/3 S[3/cos(3t)dt] replace (3t with u) and (dt with du/3) so s[3/cos9u)*(du/3)] S[1/cos(u)du]=S[sec(u)du] use back of calculus book look for S[sec(u)du]=Ln|sec(u)+tan(u)| + C replace back u=3t Ln|sec(3t)+tan(3t)| + C PS: It's supposED, not suppose . I noticed that a lot of people tend to make that grammar mistake. blackmagic: okay, I just checked with a friend of mine and he says that the answer to #19 should be (e) The soccer team only won four games the entire season. It should have been "won only" instead.
