Help with a Statistics problem ;)

Discussion in 'School Work Help' started by iris, Jul 8, 2008.

  1. iris

    iris Well-Known Member

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    I've taken stats a few years back and this is a requirement for my concentration. Any help is appreciated

    A small factory contains 3 machines (A, B, C) that produces defective and non-defective parts. It's known that:

    (i) 40% of all parts are produced on machine A;
    (ii) 20% of all parts are produced on machine C;
    (iii) 15% of all parts are defective;
    (iv) 20% of the defective parts were made on machine C;
    (v) 75% of the parts made on machine A are non-defective.

    So my question is, what is the probability that a part was either produced on machine A or is defective?

    According the manual, the answer is 0.45 but I'm trying to figure out how that answer came about.
     
  2. infinite0

    infinite0 Member

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    0.4 + .15 - 0.1 = 0.45

    ie. probability of a part produced on machine A + probability of a defective part - probability of being both
     
  3. iris

    iris Well-Known Member

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    thanks very much ;)

    I figured the first two parts out, and the last one just took me a while